Descartes' Lost Theorem
For example the sphere of radius R has constant Gaussian
curvature 1/R2 and area 4 R2;
the integral of the Gaussian curvature is 4
which is 2
times
the Euler characteristic 2.
This theorem has a polyhedral version: For any polyhedral
surface, the sum of the polyhedral curvatures is equal to
2 times the Euler characteristic.
For a convex polyhedron, with Euler characteristic 2, this is just another statement of Descartes' Lost Theorem. But it can be applied more generally, for example to a toroidal surface:
_____________________ / / /| / _____/_____ / | / / / / / / / |________/ / / / / / / / / / / / / / / / /__________/ / / / / / / /__________/_________/ / | | / |____________________|/ This polyhedral torus has 8 vertices where the curvature is |
At each of the vertices around the outside there are three
planar right angles, giving a polyhedral curvature of ![]() ![]() ![]() ![]() |
It is not clear what appeal such a calculation would have had for Descartes. Even though tesselated tori were well known as mazzochi in Italian art of the XV century, the classical subjects of interest to geometers remained convex polygons and convex polyhedra. Moreover negative curvature would not have seemed a natural concept: at the beginning of Descartes' career (he was 24 in 1620) he was reluctant to consider negative numbers at all. Finally, for Descartes the distinction between a vertex and the measure of the (planar or solid) angle at that vertex was not explicit; the lack of this distinction, probably, kept him from the combinatorial version of his theorem that Euler derived. Nevertheless his Lost Theorem, now recovered, remains as indelible evidence of the geometrical power of this intellectual giant.