The elements are denoted by the symbols derived in the Quaternionic representation of the binary tetrahedral group.
NOTE: since each element has a negative, the table should be four times as large; but $-1$ commutes with everything, so the missing products are easy to retrieve.
${\large \begin{array}
{c ||c | c | c | c | c | c | c | c | c | c | c | c ||}
& 1 & {\bf i} & {\bf j} & {\bf k} & a & a^2& b & b^2& c & c^2& d & d^2\\\hline\hline
1 & 1 & {\bf i} & {\bf j} & {\bf k} & a & a^2& b & b^2& c &c^2 & d &
d^2\\\hline
{\bf i} & {\bf i} & -1& {\bf k} & -{\bf j} & d &-c^2& c &-d^2& -b&a^2 & -\
a & b^2\\\hline
{\bf j} & {\bf j} & -{\bf k}& -1& {\bf i} & b &-d^2& -a & c^2& d &-b^2& \
-c & a^2\\\hline
{\bf k} & {\bf k} & {\bf j} & -{\bf i}& -1 & c &-b^2& -d & a^2& -a &d^2 & \
b &-c^2\\\hline
a & a & c & d & b & a^2& -1 &-c^2& {\bf j} &-d^2& {\bf k} &-b^2& {\bf i} \\\hline
a^2&a^2 &-d^2&-b^2&-c^2& -1& -a & - {\bf k}& d & -{\bf i} & b & -{\bf j} & c\
\\\hline
b & b & d & -c & -a &-d^2& -{\bf j} & b^2& -1 &-a^2& {\bf i} &-c^2&-{\bf k}\
\\\hline
b^2& b^2&-c^2& a^2& d^2& {\bf k} & c & -1 & -b & {\bf j} & d & -{\bf i} & a\
\\\hline
c & c & -a & b & -d &-b^2& -{\bf k} &-d^2& -{\bf i} & c^2& -1 &-a^2&{\bf j} \
\\\hline
c^2&c^2 & b^2&-d^2& a^2& {\bf i} & d & -{\bf j} & a & -1 & -c & {\bf k} &b \
\\\hline
d & d & -b & -a & c &-c^2& -{\bf i} &-a^2& {\bf k} &-b^2& -{\bf j} & d^2&-1\
\\\hline
d^2& d^2& a^2& c^2&-b^2& {\bf j} & b & {\bf i} & c & -{\bf k} & a & -1 &-d\
\\\hline\hline
\end{array}}$
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